langkahnya di tunggu....

Penjelasan dengan langkah-langkah:
a. (1/2)'3x(1/2)’2=(1x1x1/2x2x2)(1x1/2x2)
=1/8 x 1/4
=1x1/8x4
=1/32
b. (2/3)'5x(2/3)'-5=(2x2x2x2x2/3x3x3x3x3x)1/ (2/3)'-5
=(32/243)/32/243
=1
[answer.2.content]Penjelasan dengan langkah-langkah:
a. (1/2)'3x(1/2)’2=(1x1x1/2x2x2)(1x1/2x2)
=1/8 x 1/4
=1x1/8x4
=1/32
b. (2/3)'5x(2/3)'-5=(2x2x2x2x2/3x3x3x3x3x)1/ (2/3)'-5
=(32/243)/32/243
=1
[answer.2.content]